等差数列{an}中,a1

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等差数列{an}中,a1

等差数列{an}中,a1
等差数列{an}中,a1

等差数列{an}中,a1
an =a1+(n-1)d
S9=S12
(a1+4d)9 = (2a1+11d)6
a1=-10d ( a1d >0)
Sn = (2a1+(n-1)d) n/2
=d(n^2-21n)/2
=(d/2)[( n-21/2)^2 -441/4]
max Sn at n = 10 or 11

S12-S9=a12+a11+a10=0
3a11=0
a11=0
a10<0 a12>0

Sn最小时 n=10或11