作业帮matlab 求一个有理多项式系统的频率响应!有理多项H(z)的分子和分母系数表示为：B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]；A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243].绘制系统H(z)的幅度和
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![matlab 求一个有理多项式系统的频率响应!有理多项H(z)的分子和分母系数表示为：B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]；A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243].绘制系统H(z)的幅度和](/uploads/image/z/9933559-7-9.jpg?t=matlab+%E6%B1%82%E4%B8%80%E4%B8%AA%E6%9C%89%E7%90%86%E5%A4%9A%E9%A1%B9%E5%BC%8F%E7%B3%BB%E7%BB%9F%E7%9A%84%E9%A2%91%E7%8E%87%E5%93%8D%E5%BA%94%21%E6%9C%89%E7%90%86%E5%A4%9A%E9%A1%B9H%28z%29%E7%9A%84%E5%88%86%E5%AD%90%E5%92%8C%E5%88%86%E6%AF%8D%E7%B3%BB%E6%95%B0%E8%A1%A8%E7%A4%BA%E4%B8%BA%EF%BC%9AB%3D%5B0.9122+-1.0792+1.1540+-1.1765+1.1540+-1.0792+0.9122%5D%EF%BC%9BA+%3D%5B1.0000+-1.1499+1.1920+-1.1765+1.1159+-1.0085+0.8243%5D.%E7%BB%98%E5%88%B6%E7%B3%BB%E7%BB%9FH%28z%29%E7%9A%84%E5%B9%85%E5%BA%A6%E5%92%8C)
matlab 求一个有理多项式系统的频率响应!有理多项H(z)的分子和分母系数表示为：B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]；A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243].绘制系统H(z)的幅度和
matlab 求一个有理多项式系统的频率响应!
有理多项H(z)的分子和分母系数表示为：
B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]；
A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243].
绘制系统H(z)的幅度和相位响应
求高人指教,这样不对吗?怎么差别那么大?
figure;
B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122];
A=[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243];
N=1000;
[H,W] =freqz(B,A,'whole');
L = 20 * log10(abs(H));
subplot(2,1,1);
plot(W/pi,L); grid;
axis([0,2,-30,20]);
xlabel('\omega (x\pi)');
ylabel('20*log_1_0|H(e^j^\omega)|');
subplot(2,1,2);
plot(W/pi,angle(H)/pi); grid;
xlabel('\omega (x\pi)');
ylabel('
matlab 求一个有理多项式系统的频率响应!有理多项H(z)的分子和分母系数表示为：B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]；A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243].绘制系统H(z)的幅度和
在matlab的命令窗口中输入经下内容：
B=[0.9122 -1.0792 1.1540 -1.1765 1.1540 -1.0792 0.9122]
A =[1.0000 -1.1499 1.1920 -1.1765 1.1159 -1.0085 0.8243]
G=tf(B,A)
bode(G)
就行了.得到图形的上边一幅是幅度,下边是相位图.