求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!

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求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!

求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!
求高数极限,明天要考试了,
π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!

求高数极限,明天要考试了,π/n乘以(cos^2π/n+cos^22π/n……cos(n-1)π/n),当n趋向与无穷时的极限!