s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i

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s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i
s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊
s=5
for i 2.6 to 4.9 step 0.6
s=s+1
next i

s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i
s=5
从i=2.6开始,每次i加0.6(直到i>4.9),s加1
如果i>4.9
则停止.

这个结果是9么亲我这书上答案是8啊我算的也是9

i 由 2.6 到 4.9, 每次回圈 i + 0.6 翅到4.9 或最接近 4.9(少於4.9)便完结回圈
而s开始值是5, 每次回圈 s 加 1, 直到回圈结束

S=9

当验证程序的时候最好的方法是用print 语句，在你的这段程序后面加上print s,print i就可以看到你运行的结果了，s=9,i=5.0这样你就了解你所运算程序了。

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