sin21°cos189°-sin69°sin9°的值为

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sin21°cos189°-sin69°sin9°的值为

sin21°cos189°-sin69°sin9°的值为
sin21°cos189°-sin69°sin9°的值为

sin21°cos189°-sin69°sin9°的值为
用到的公式:[cos(180°+A)=-cosA/sin(90°-A)=cosA/sin(A+B)=sinAcosB+cosAsinB]
因为cos189°=cos(180°+9°)=-cos9°
和sin69°=sin(90°-21°)=cos21°
所以
sin21°cos189°-sin69°sin9°
=-sin21°cos9°-cos21°sin9°
=-(sin21°cos9°+cos21°sin9°)
=-sin(21°+9°)
=-sin30°
=-(1/2)
++++希望可以帮助你 我也可以加分哟 哈哈

用诱导公式和两角和的正弦公式得出-1/2

根据诱导公式,
角度制下的角的表示:
sin(180°+α)=-sinα
cos(180°+α)=-cosα
tan(180°+α)=tanα
角度制下的角的表示:
sin (90°-α)=cosα
cos (90°-α)=sinα
tan (90°-α)=cotα
sin21°cos189°-sin69°sin9°=-sin21cos9-cos21sin9=-sin30=-1/2

原式=sin(90°-69°)cos(180°+9°)-sin69°sin9°=cos69°(-cos9°)-sin69°sin9°=-(cos69°cos9°+sin69°sin9°)=-cos(69°-9°)=-cos60°=-1/2