计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x

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计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x

计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x
计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x

计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x
[(1+2/x)-(x+1)/(x-2)]/[(x+4)/(x^2-2x)]
=[(x+2)/x-(x+1)/(x-2)]*[(x^2-2x)/(x+4)]
=[(x+2)(x-2)-x(x+1)]/(x-2)]*[(x^2-2x)/(x+4)]
=[(-x-4)/(x-2)]*[x(x-2)/(x+4)]
=-[(x+4)/(x-2)]*[x(x-2)/(x+4)]
=-x

.(1+2/x-x+1/x-2)除以x+4/x平方-2x
=(x(x-2)+2(x-2)+x(x+1))/x(x-2) *x(x-2)/(x+4)
=(x(x-2)+2(x-2)+x(x+1))/x(x-2) *x(x-2)/(x+4)
=(x^2-2x+2x-4+x^2+x)/x(x-2) *x(x-2)/(x+4)
=(2x^2-4+x)/(x+4)