作业帮1.计算①(x-1-x+1分之8)×x+3分之x+1；②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y；③（x-x+1分之2x）÷x²-1分之x²-2x+1④（x²-2x分之x+2-x²-4x+4分之x-1）÷x³-2x²分之x-4
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/26 23:33:53
1.计算①(x-1-x+1分之8)×x+3分之x+1；②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y；③（x-x+1分之2x）÷x²-1分之x²-2x+1④（x²-2x分之x+2-x²-4x+4分之x-1）÷x³-2x²分之x-4
1.计算①(x-1-x+1分之8)×x+3分之x+1；
②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y；③（x-x+1分之2x）÷x²-1分之x²-2x+1
④（x²-2x分之x+2-x²-4x+4分之x-1）÷x³-2x²分之x-4
1.计算①(x-1-x+1分之8)×x+3分之x+1；②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y；③（x-x+1分之2x）÷x²-1分之x²-2x+1④（x²-2x分之x+2-x²-4x+4分之x-1）÷x³-2x²分之x-4
①(x-1-x+1分之8)×x+3分之x+1；
=（x²-1-8）/(x+1)×(x+1)/(x+3)
=x-3;
②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y；
=(x-y)/(x+3y)×(x+3y)²/(x+y)(x-y)-2y/(x+y)
=(x+3y)/(x+y)-2y/(x+y)
=1;
③（x-x+1分之2x）÷x²-1分之x²-2x+1
=(x²+x-2x)/(x+1)×(x+1)(x-1)/(x-1)²
=x(x-1)/(x-1)
=x;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
①(x-1-x+1分之8)×(x+3)分之(x+1)
=[(x+1)分之（x²-1-8)]×[(x+3)分之(x+1)]
=[(x+1)分之（x-3)(x+3)]×[(x+3)分之(x+1)]
=x-3
②(x+3y)分之(x-y)÷(x²+6xy+9y²)分之(x²-y²)-(x+y)分之2y
...
全部展开
①(x-1-x+1分之8)×(x+3)分之(x+1)
=[(x+1)分之（x²-1-8)]×[(x+3)分之(x+1)]
=[(x+1)分之（x-3)(x+3)]×[(x+3)分之(x+1)]
=x-3
②(x+3y)分之(x-y)÷(x²+6xy+9y²)分之(x²-y²)-(x+y)分之2y
=(x+3y)分之(x-y)÷(x+3y)²分之(x-y)(x+y)-(x+y)分之2y
=(x+y)分之(x+3y)-(x+y)分之2y
=(x+y)分之(x+3y-2y)
=(x+y)分之(x+y)
=1
③（x-x+1分之2x）÷(x²-1)分之(x²-2x+1)
=[(x+1)分之(x²+x-2x)]÷[(x-1)(x+1)分之(x-1)²]
=[(x+1)分之x(x-1)]÷[(x+1)分之(x-1)]
=x
④（x²-2x)分之(x+2)-(x²-4x+4)分之(x-1）÷(x³-2x²)分之(x-4)
=[x(x-2)分之(x+2)-(x-2)²分之(x-1）]÷[x²(x-2)分之(x-4)]
=[x(x-2)²分之(x²-4-x²+x)]÷[x²(x-2)分之(x-4)]
=[x(x-2)²分之(x-4)]÷[x²(x-2)分之(x-4)]
=(x-2)分之x
收起