(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)

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(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)

(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)
(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)

(X2-X1)-[(X2-X1)/(X1X2)]是怎样得到(X2-X1)(1-1/X1X2)
(X2-X1)-[(X2-X1)/(X1X2)]提取公因式(X2-X1)得到(X2-X1)(1-1/X1X2)

提取x2-x1
所以=(x1-x2)(1-1/(x1x2)

(X2-X1)-[(X2-X1)/(X1X2)]提取公因式(X2-X1)就得
(X2-X1)(1-1/X1X2)

提出公因式(X2-X1)得到

  相同项 提取公因式

  (X2-X1)-[(X2-X1)/(X1X2)]
 
 =(X2-X1)*1-[(X2-X1)/(X1X2)]
 
 =(X2-X1)(1-1/X1X2)