U={(x,y)|x∈R,y∈R},A={(x,y)|2x-y+a>0},B={(x,y)|x+2y-b≤0},则点P(1,4)∈A∩(CuB)的充要条件是.( )A.a>2,b>9 B.a<2,b>9 C.a>2,b<9 D.a<2,b<9

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U={(x,y)|x∈R,y∈R},A={(x,y)|2x-y+a>0},B={(x,y)|x+2y-b≤0},则点P(1,4)∈A∩(CuB)的充要条件是.( )A.a>2,b>9 B.a<2,b>9 C.a>2,b<9 D.a<2,b<9

U={(x,y)|x∈R,y∈R},A={(x,y)|2x-y+a>0},B={(x,y)|x+2y-b≤0},则点P(1,4)∈A∩(CuB)的充要条件是.( )A.a>2,b>9 B.a<2,b>9 C.a>2,b<9 D.a<2,b<9
U={(x,y)|x∈R,y∈R},A={(x,y)|2x-y+a>0},B={(x,y)|x+2y-b≤0},则点P(1,4)∈A∩(CuB)的充要条件是.( )
A.a>2,b>9 B.a<2,b>9 C.a>2,b<9 D.a<2,b<9

U={(x,y)|x∈R,y∈R},A={(x,y)|2x-y+a>0},B={(x,y)|x+2y-b≤0},则点P(1,4)∈A∩(CuB)的充要条件是.( )A.a>2,b>9 B.a<2,b>9 C.a>2,b<9 D.a<2,b<9
选C
CuB={(x,y)/x+2y-b>0}
所以A交CuB就是M={(x,y)/x+2y-b>0,2x-y+a>0}
因为P(1,4)属于该集合M,所以将x=1,y=4代入,得到不等式组
9-b>0
-2+a>0
解之即可

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