已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²

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已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²

已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²
已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²

已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²
x(x+y)(x-y)-x(x+y)²
=x(x+y)[(x-y)-(x+y)]
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2×(-1/2)×1
=1

X(X^2-Y^2)-X(X^2+Y^2+2XY)=x^3-xy^2-x^3+xY^2-2xy=2xy=-1

由已知,有
x+y=1,xy=-1/2,x²-x=1/2
于是
x(x+y)(x-y)-x(x+y)²
=x·1·(x-y)-x·1²
=x²-xy-x
=x²-(-1/2)-x
=x²-x+1/2
=1/2+1/2
=1
或者先化简:
x(x+y)(...

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由已知,有
x+y=1,xy=-1/2,x²-x=1/2
于是
x(x+y)(x-y)-x(x+y)²
=x·1·(x-y)-x·1²
=x²-xy-x
=x²-(-1/2)-x
=x²-x+1/2
=1/2+1/2
=1
或者先化简:
x(x+y)(x-y)-x(x+y)²
=x(x+y)[(x-y)-(x+y)]
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2×(-1/2)×1
=1

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