matlab中a(i)=1/sqrt(2)是什么意思

matlab中a(i)=1/sqrt(2)是什么意思 mk=a(randint(1)+1)*sqrt(2)/2+i*a(randint(1)+1)*sqrt(2)/2 请教MATLAB大神,这个语句的意思是什么? matlab中出现?In an assignment A(I) = B,the number of elements in B and I must be the same.clear;R=5;Z=2*pi*R;Lambda=300;c=3*10^8;Omega=1:10;for g=1:length(Omega)Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)] Error using ==> mtimes Inner matrix dimensions must agree 用matlab求解时出现错误x=0:1:12;a=sqrt(10.08+0.5*sqrt(406.43+31.7*x.^2));b=sqrt(-10.08+0.5*sqrt(406.43+31.7*x.^2));c=1./(2*cos(0.115*sqrt(5.63i*x+20.16))); y=0;f=499800*(abs(c)).^2*x*(e y=sqrt(1-x^2)在MATLAB中哪里错了 matlab程序 解方程组syms a b Rsd Rspf1=72.8*(1+cos(a))-2*(sqrt(51*Rsp)+sqrt(21.8*Rsd));f2=50.8*(1+cos(b))-2*(sqrt(2.3*Rsp)+sqrt(48.5*Rsd));A=input('输入：A=');B=input('输入：B=');for i=1:length(A)a=A(i);b=B(i);f11=subs(f1);f22=subs(f2);[Rs matlab fzero 问题function v=dxt2(x1,x2)n=0.0109;d=sqrt((x2(1)-x1(1))^2+(x2(2)-x1(2))^2);i=(x2(2)-x1(2))/d;y=2.5*sqrt(n)-0.13-0.75*sqrt(2.2/4)*(sqrt(n)-0.1);x=fzero(@(x)1/n*2.2/4*(1-sin(x)/x)^(y+1/2)*2.2^2/8*(x-sin(x))*sqrt(i)-0.6,0.5);a=2.2^2/8*(x- matlab中表达式sqrt((M[i][j+3]-M[i][j]).^2+(M[i][j+4]-M[i][j+1]).^2)错在哪里 matlab解方程遇到困难,急救!solve('A*sqrt(19.6.*(3-A))*(sqrt(3-A)/4.9)+sqrt(2/4.9))=1-A*A','A');错哪了?麻烦帮我改过来~一定给悬赏 求高手解答用Matlab 如何在matlab编程求这个方程组的解啊?已知a,b,c方程组72.8*(1+cos(a)）=2*(SQRT(x*21.8)+SQRT(25.5*y)+SQRT(25.5*z))50.8*(1+cos(b))=2*SQRT(x*50.8)48*(1+cos(c))=2*(SQRT(x*29)+SQRT(47*y)+SQRT(1.92*z))求x,y,z假设 matlab求解多元线性方程时遇到问题我想用solve命令解决一个六元线性方程组,我的matlab语句如下：Z=solve('B=D+F=1','A+C+E=0','B+sqrt(3)*D-sqrt(3)*F=0','B+sqrt(3)*C+D-sqrt(3)*E=0','-A+2*C+sqrt(3)*D+2*E-sqrt(3)*F=0','B+sqrt 一个Matlab的程序求圆周率别人写了一个割圆术求圆周率的matlab程序但是实施不了总是出现问题function y=calpi(n)syms a;for i=1:na=sqrt(2-sqrt(4-a^2));enda=subs(a,'a','1')y=3*2^n*vpa(a,n+5)另外谁能解释一下最后 怎么样用matlab求一个含有未知数的矩阵的逆矩阵比如：A=[s,0,0,a*i*sqrt[(b+1)(c+1)];0,s,a*i*sqrt[b*c]其中sabc为未知数 matlab 编程 A(i,j)=sqrt((i-j)^2+6^2)*40 生成一个7*7的矩阵,矩阵中对应的数据由上面的方程得到. MATLAB 中 复数的问题,x=sqrt（2）*exp（i*（3*pi/4）） 其结果为x=-1+1i,为什么不是x=1+-i 呢 查看程序错误在哪clearinputn: to ndime v(n)for i=1 to n step 1s=sqrt(0.0001+(0.0004+0.02*(sqrt(1.8*i-0.0001*i^2)-sqrt(1.8*(i-1)-0.0001*(i-1)^2)))^2)a=10.05*sin(atan(0.04+0.02*(sqrt(18000*i-i^2)-sqrt(18000*(i-1)-(i-1)^2))))+1.05*cos(atan(0.04 matlab中A(i,2: 用matlab如何解出1的立方根(-1+sqrt(3)i)/2