求方程5x2-6xy+2y2-4x+2y+1=0的实数根
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求方程5x2-6xy+2y2-4x+2y+1=0的实数根
求方程5x2-6xy+2y2-4x+2y+1=0的实数根
求方程5x2-6xy+2y2-4x+2y+1=0的实数根
(9x^2-6xy+y^2)-(4x^2+4x+1)+(y^2+2y+1)+1=0
(3x+y)^2-(2x+1)^2+(y+1)^2+1=0
x=1;y=1
你先把方程改成有关X的方程,然后得到5X2-(6y+4)x+2y2+2y+1=0,再用判别式,即B2-4aC=0
解得Y,代入5X2-(6y+4)x+2y2+2y+1=0既可
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