化简 [ sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B) ]要完整,

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/09 08:19:32
化简 [ sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B) ]要完整,

化简 [ sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B) ]要完整,
化简 [ sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B) ]
要完整,

化简 [ sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B) ]要完整,
[sin(270°+B) × sin(90°-B) × cot(B-270°) ] / [ sin(-B) × cos(270°-B) × cot(180°-B)]
=[-cosBcosB(-tanB)]/[(-sinB)(-sinB)(-cotB)]
=-[cosBcosBtanB]/[sinBsinBcotB]
=-cotBcotBtanB/cotB
=-1