[a-b][x-y]-[b-a][x+y]的解法

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[a-b][x-y]-[b-a][x+y]的解法
[a-b][x-y]-[b-a][x+y]的解法

[a-b][x-y]-[b-a][x+y]的解法
[a-b][x-y]-[b-a][x+y]
=[a-b][x-y]+[a-b][x+y]
=[a-b][x-y+x+y]
=2x[a-b]

原式=(a-b)(x-y)+(a-b)(x+y)
=(a-b)(x-y+x+y)
=2x(a-b)

=(a-b)(x-y)+(a-b)(x+y)
=(a-b)(x-y+x+y)
=2x(a-b)

原式
=(a-b)(x-y)＋(a-b)(x＋y)
=(a-b)(x-y＋x＋y)
=(a-b)2x
=2ax-2bx

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