已知tana/2=2则tan(a+π/4)=?6sina+cosa/3sina-2cosa=?

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已知tana/2=2则tan(a+π/4)=?6sina+cosa/3sina-2cosa=?

已知tana/2=2则tan(a+π/4)=?6sina+cosa/3sina-2cosa=?
已知tana/2=2则tan(a+π/4)=?6sina+cosa/3sina-2cosa=?

已知tana/2=2则tan(a+π/4)=?6sina+cosa/3sina-2cosa=?
tana=2tana/(1-tana*tana)=-4/3
tan(a+π/4)=(tana+tanπ/4)/(1-tana*tanπ/4)=1/7
6sina+cosa/3sina-2cosa=(6sina/cosa+1)/(3sina/cosa-2)
=(6tana+1))/(3tana-2)
=7/6

tan(a+π/4)=(tana+tanπ/4)/(1-tanatanπ/4)
又因为tana=-4/3
所以tan(a+π/4)=-7
tana=sina/cosa=-4/3既sina=-4/3cosa
6sina+cosa/3sina-2cosa=7/6