作业帮y'=sec²(x+y)* (1+y')怎么变到y'=sec²(x+y)/[1-sec²(x+y)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 09:05:26
![y'=sec²(x+y)* (1+y')怎么变到y'=sec²(x+y)/[1-sec²(x+y)]](/uploads/image/z/6862060-28-0.jpg?t=y%27%3Dsec%26%23178%3B%28x%2By%29%2A+%281%2By%27%29%E6%80%8E%E4%B9%88%E5%8F%98%E5%88%B0y%27%3Dsec%26%23178%3B%28x%2By%29%2F%5B1-sec%26%23178%3B%28x%2By%29%5D)
y'=sec²(x+y)* (1+y')怎么变到y'=sec²(x+y)/[1-sec²(x+y)]
y'=sec²(x+y)* (1+y')怎么变到y'=sec²(x+y)/[1-sec²(x+y)]
y'=sec²(x+y)* (1+y')怎么变到y'=sec²(x+y)/[1-sec²(x+y)]
将右边的括号拆开,带有y'的项移到左边,提出y',将y'前面的系数项除到右边就行了.