计算:1/1*3+1/2*4+1/3*5+...+1/9*11=?

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计算:1/1*3+1/2*4+1/3*5+...+1/9*11=?

计算:1/1*3+1/2*4+1/3*5+...+1/9*11=?
计算:1/1*3+1/2*4+1/3*5+...+1/9*11=?

计算:1/1*3+1/2*4+1/3*5+...+1/9*11=?
1/(1×3)=1/2*(1-1/3),1/(2×4)=1/2*(1/2-1/4),1/(3×5)=1/2*(1/3-1/5),…,1/(9×11)=1/2*(1/9-1/11)
所以原式=1/2*(1-1/3+1/2-1/4+1/3-1/5+……+1/9-1/11)
=1/2*(1-1/11+1/2-1/10)
=1/2*(10/11+2/5)
=1/2*72/55
=36/55

=1/2*(1-1/3+1/2-1/4+1/3-1/5+……+1/9-1/11)
=1/2*(1+1/2-1/10-1/11)
=36/55

1/{n(n+2)] = (1/2)(1/n - 1/(n+2))
1/1*3+1/2*4+1/3*5+...+1/9*11
= (1/2) ( (1/1-1/3) +(1/2-1/4) +..+(1/9-1/11) )
=(1/2)( 1+ 1/2 -1/10-1/11)
= (1/2) (144/110)
= 72/110
= 36/55