matlab 问题 求大神>> ['t' num2str(1) num2str(2)]ans =t12>> a=[sym(['t' num2str(1) num2str(2)])-2 x+3] a = [ t12 - 2, x + 3] >> solve(a)ans = t12: [1x1 sym] x: [1x1 sym]>> a.['t' num2str(1) num2str(2)] a.['t' num2str(1) num2str(2)] |E

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matlab 问题 求大神>> ['t' num2str(1) num2str(2)]ans =t12>>  a=[sym(['t' num2str(1) num2str(2)])-2 x+3] a = [ t12 - 2, x + 3] >> solve(a)ans =     t12: [1x1 sym]       x: [1x1 sym]>> a.['t' num2str(1) num2str(2)] a.['t' num2str(1) num2str(2)]  |E

matlab 问题 求大神>> ['t' num2str(1) num2str(2)]ans =t12>> a=[sym(['t' num2str(1) num2str(2)])-2 x+3] a = [ t12 - 2, x + 3] >> solve(a)ans = t12: [1x1 sym] x: [1x1 sym]>> a.['t' num2str(1) num2str(2)] a.['t' num2str(1) num2str(2)] |E
matlab 问题 求大神
>> ['t' num2str(1) num2str(2)]
ans =
t12
>> a=[sym(['t' num2str(1) num2str(2)])-2 x+3]

a =

[ t12 - 2, x + 3]

>> solve(a)
ans =
t12: [1x1 sym]
x: [1x1 sym]
>> a.['t' num2str(1) num2str(2)]
a.['t' num2str(1) num2str(2)]
|
Error: Unbalanced or unexpected parenthesis or bracket.
为什么最后一行输入有错

matlab 问题 求大神>> ['t' num2str(1) num2str(2)]ans =t12>> a=[sym(['t' num2str(1) num2str(2)])-2 x+3] a = [ t12 - 2, x + 3] >> solve(a)ans = t12: [1x1 sym] x: [1x1 sym]>> a.['t' num2str(1) num2str(2)] a.['t' num2str(1) num2str(2)] |E
a.['t' num2str(1) num2str(2)]
一、a后面那个点什么意思?没有这样表示的,
二、a[、、、] 也没有这样表示的,这个公式的目的是什么
三 ['t' num2str(1) num2str(2)]=t12,那你a.t12真不明白是干嘛的 注: a是符号数组