作业帮计算 [2x²-(x-y)(x+y)][(2-x)(2+x)+(y-2)(y+2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/02 04:07:32
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计算 [2x²-(x-y)(x+y)][(2-x)(2+x)+(y-2)(y+2)]
计算 [2x²-(x-y)(x+y)][(2-x)(2+x)+(y-2)(y+2)]
计算 [2x²-(x-y)(x+y)][(2-x)(2+x)+(y-2)(y+2)]
[2x²-(x-y)(x+y)][(2-x)(2+x)+(y-2)(y+2)]
=[2x²-x²+y²][4-x²+y²-4]
=[x²+y²][y²-x²]
=y^4-x^4
=（2x^2-x^2+y^2)(4-x^2+y^2-4)=(x^2+y^2)(y^2-x^2)=y^4-x^4
原式=【2x*x-（x*x-y*y）】【4-x*x+y*y-4】
=（y*y-x*x）（y*y-x*x）
=（y+x）（y+x）（y-x）（y-x）