1. If x and y are integers and xy+x^2 is oddh which of the following statements must be true?① x is odd② y is odd③ x+y is oddA. ①B. ③C. ① and ②D. ① an

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1. If x and y are integers and xy+x^2 is oddh which of the following statements must be true?① x is odd② y is odd③ x+y is oddA. ①B. ③C. ① and ②D. ① an

1. If x and y are integers and xy+x^2 is oddh which of the following statements must be true?① x is odd② y is odd③ x+y is oddA. ①B. ③C. ① and ②D. ① an
1. If x and y are integers and xy+x^2 is oddh which of the following statements must be true?① x is odd② y is odd③ x+y is oddA. ①B. ③C. ① and ②D. ① and ③E. ② and ③2. For how many integers n is (2n+1)(3n-1) a negative number?A. NoneB. OneC. TwoD. ThreeE. Four求详解

1. If x and y are integers and xy+x^2 is oddh which of the following statements must be true?① x is odd② y is odd③ x+y is oddA. ①B. ③C. ① and ②D. ① an
1、x和y都是整数,“xy+x^2是奇数”就是说:x*(x+y)是奇数.
我觉得这道题问的是哪种组合是正确的.因为单独看,①②③都是推不出来的【也就是说A和B不对】,如果x是奇数,y也是奇数,那么x+y成了偶数,x*(x+y)也就成了偶数【所以C是不对的】,如果y和x+y都是奇数,那么x是偶数了,x*(x+y)也还是偶数【所以E也不对】,只有x和x+y都是奇数时,能证明x*(x+y)是奇数,所以D是正确答案.
2、要想让(2n+1)(3n-1)的值为负数,n有几种可能?
这道题是解不等式.根据题意,
要么是:2n+10
要么是:2n+1>0且3n-1

  1. D xy+x*x=x(x+y) 这个是奇数就说明,X和X+Y都是奇数,因为只有两个奇数相乘才是奇数

  2. B 两个括号乘积是负数,说明两个括号肯定是一正一负

    1)2n+1>0,3n-1<0 得(-0.5,1/3)

    2)  2n+1<0,3n-1>0 五届

    解两组不等式,取并集,得到(...

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    1. D xy+x*x=x(x+y) 这个是奇数就说明,X和X+Y都是奇数,因为只有两个奇数相乘才是奇数

    2. B 两个括号乘积是负数,说明两个括号肯定是一正一负

      1)2n+1>0,3n-1<0 得(-0.5,1/3)

      2)  2n+1<0,3n-1>0 五届

      解两组不等式,取并集,得到(-0.5,1/3)

      然后取整数,只有0.

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