计算：[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(-2y)

来源：学生作业帮助网编辑：作业帮时间：2024/04/18 12:58:13

计算：[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(-2y)
计算：[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(-2y)

计算：[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(-2y)
原式=【（X-Y)(X+Y-X+Y)+2Y(X-Y)】/-2y
=【2y(x-y)+2y(x-y)】/-2y
=4y(x-y)/-2y
=-2(x-y)

=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]/(-2y)
=(x^2-y^2-x^2+2xy-y^2+2xy-2y^2)/(-2y)
=(4xy-4y^2)/(-2y)
=-2x+2y

[(x+y)(x-y)-(x-y)²+2y(x-y)]/(-2y)
=(x-y)[(x+y)-(x-y)+2y]/(-2y)
=(x-y)(x+y-x+y+2y)/(-2y)
=4y(x-y)/(-2y)
=-2(x-y)
=2y-2x

={(X-Y)[X+Y-(X-Y)+2Y]}/(-2Y)
=[4Y(X-Y)]/(-2Y)
=-2Y(X-Y)
=-2XY+2Y^2

这种题目不难，一步一步慢慢来就行了

原式=(x-y)[(x﹢y)-(x-y)﹢2y] ∕ (-2y)=(x-y)4y ∕ (-2y)=-2(x-y)=2y-2x

[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(-2y）
=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]/(-2y)
=[4xy-4y^2]/(-2y)
=2y-2x

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