(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 19:42:22
(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字

(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字
(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字

(1)计算:(2+1)(2^2+1)(2^4+1)……(2^32+1) (2) 试求(1)中结果的个位数字
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
= (2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
= ...
= 2^64-1