[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1

来源：学生作业帮助网编辑：作业帮时间：2024/05/12 16:38:00

[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1
[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1

[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1
[(x-y)^2+(x+y)(x-y)]÷2x
=(x-y)[(x-y)+(x+y)]÷2x
=(x-y)(x-y+x+y)÷2x
=2x(x-y)÷2x
=x-y
=2011-1
=2010

不懂

[(x-y)^2+(x+y)(x-y)]÷2x
=(x-y)(x-y+x+y)÷2x
=(x-y)*2x÷2x
=x-y
=2011-1
=2010

[(x-y)^2+(x+y)(x-y)]÷2x=(x-y)[(x-y)+(x+y)]÷2x=2x(x-y)÷2x=x-y=2011-1=2010

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 化简y(x+y)+(x+y)(x-y)-x^2 (x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 因式分解x(x+y)(x-y)-x(x+y)^2 {(x,y) |x|+|y| x>y?x:y [(x-y)^2-(x+2y)(x-2y)]/y 计算:y-x分之x+y+x-y分之y-y-x分之2x-y x^2(x-y)+(y-x) x(x-y)2-(y-x)3 【(x-y)^2+(x+y)(x-y)】除以 2x [(x-y)²+(x+y)(x-y)]除以2x [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x 化简：[(x+y)(x-y)(x+y)^2-2y(x-2y)](-2y) 谢谢!