xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1

来源：学生作业帮助网编辑：作业帮时间：2024/04/27 23:02:55

xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y) - y×x²/(x²+x)=
(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=
2a/(a²-4) - 1/(a-2)=
2/(1-a ) - 1/(a-1)=
x²-1/(x²-x-2)除以x/2x-4,其中x=1/2
[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1

xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y) - y×x²/(x²+x)=y/x-x²y/x(x+1)=y/x-xy/x+1=((x+1)y-x²y)/x(x+1)=(xy+y-x²y)/x(x+1)
(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=x(x-3)/(-9x²)-10/(x-3)²=(x-3)/(-9x)-10/(x-3)²=((x-3)^3+90x)/9x(3-x)
2a/(a²-4) - 1/(a-2)=2a/(a+2)(a-2)-1/(a-2)=(2a-a-2)/(a+2)(a-2)=1/(a+2)
2/(1-a ) - 1/(a-1)=(-2-1)/(a-1)=(-3)/(a-1)
x²-1/(x²-x-2)除以x/2x-4,其中x=1/2
解:原式=((x+1)(x-1)/(x+1)(x-2))/(x*2(x-2))
=(x-1)/(x-2)/x/2/(x-2)
=(x-1)/(2x(x-2)²)
当x=1/2时,原式=(-1/2)/(9/4)=-2/9
[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
原式=((x(x+1)-x)/(x+1))/(x/(2(x-2)))
=(x²/(x+1))/(x/2/(x-2))
=x²/(x+1)/x*2*(x-2)
=2x(x-2)/(x+1)
当x=√2+1时,原式=(2√2+2)(√2+1)(√2-1)/(√2+2)
=(2√2+2)/(√2+2)
顺便问一下,你这是哪找的题?我做了近一小时!不对回来找我

0.5x²+xy+0.5y² 因式分解：x²-xy-12y² 4x²y-xy² -9x²-y²+6xy x²-2xy+y²-9 6xy²-9x²y-y²因式分解若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 因式分解 x²-2xy+y²-z² 计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急（x²+y²)²-x²y²=(x²+y²)²-(xy)²=(x²+y²+xy)(x²+y²-xy)=(x+y)²(x-y)²-xy+xy=(x+y)²(x-y)² x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy x²y²-x²y-xy²+x+y-1因式分解已知x²y²+x²+y²=10xy-16 求x,y 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy x²-y²+6x+9分之x²+y²-9-2xy 3x²-y²=8x²＋xy＋y²=4 因式分解 x²-XY-2y²-X-Y