极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?

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极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1  问lim【sin(x+π)】/x =lim(-sinx)/x  这步怎么出来的?

极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?
极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1

问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?

极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?
中学:sin(x+π) = - sinx
高数:lim(x->0) sinx / x = 1